1. Tentukan akar-akar persamaan kuadrat berikut: a. 2x²+x-6=0 b. (x+3)2-25= 0
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Jawaban:
a. 2x²+x-6=0
(2x-3)(x+2)=0
2x = 3
x = 3/2 = 1 1/2
dan x = -2
b. (x+3)2-25=0
2x + 6 -25 =0
2x = 25 - 6
2x = 19
x = 19/2 = 9 1/2
Jawaban:
A. x1 = 3/2 dan x2 = -2
B. x = 19/2
Penjelasan dengan langkah-langkah:
A.
[tex]2 {x}^{2} + x - 6 \\ = (2x - 3)(x + 2) \\ x1 = 2x - 3 = 0 \\ x1 = \frac{3}{2} \\ x2 = x + 2 = 0 \\ x2 = - 2[/tex]
B.
[tex](x + 3)2 - 25 = 0 \\2x + 6 - 25 = 0 \\ 2x - 19 = 0 \\ x = \frac{19}{2} [/tex]
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